A body is projected vertically up from ground with a velocity `u` so as to reach maximum height 'h'. At half of the maximum height its velocity will be

A body is projected vertically up with a valocity u. its velocity at ghalf of its maximum height and at 3//4th of its maximum height are.

A ball is projected from the ground with velocity u such that its range is maximum Then

When a body is projected vertically up from ground, its velocity is reduced to 1/3 rd of initial velocity at height 'y' above the ground. Then maximum height reached by the body is

A body is projected vertically up from surface of the earth with a velocity half of escape velocity. The ratio of its maximum height of ascent and radius of earth is

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A body is projected with velocity u so that its horizontal range is twice the maximum height.The range is

A particle is projected vertically up with velocity v=sqrt((4gR_e)/3) from earth surface.The velocity of particle at height equal to half of the maximum height reached by it

A body is thrown vertically upward with velocity u . The ratio of times at which it is at particular height h is 1 : 2 . What is the maximum height reached by the body above point of projection ?

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is