A force of 10N acts on a body of mass 1.0kg at rest. Find the work done in 4 seconds

Explanation

`F=10N, m= 1.0kg , u= 0, t= 4s`, acceleration `a= (F )/(m) = (10)/(1) = 10ms^(-2)`
Its displacement `S= u t + (1)/(2) a t^(2)= 0 + (1)/(2) (10)4^(2)= 80m`
The work done W= FS = ma S = 1.0 xx 10 xx 80 = 800J`