A particle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becomes 0.2J, then the minimum and maximum value of 'v' are

Explanation

In case of perfectly inelastic collision the velocity of combined mass will be `v//2`
`therefore KE = (1)/(2) (2m) ((v^(2)),(4))` i.e., `(0.2) = (1)/(2) (0.2) ((v^(2))/(4)) rArr v= 2 sqrt2 m//s`
In case of perfectly elastic collision, first particle stops and the second acquires the same velocity v
`KE = (1)/(2) mv^(2)` i..e., `0.2 = (1)/(2) (0.1)v^(2)rArr v= 2 m//s`
Therfore, minimum value of v is 2m/s in case of perfectly elastic collision and maximum value of v is `2 sqrt2 m//s` in case of perfectly inelastic collision.