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cos theta + cos 2 theta + cos 3 theta + ...

`cos theta + cos 2 theta + cos 3 theta + …. + cos { (n-1) theta}+ cos n theta=`

A

`(cos { (1)/(2) (n+1) theta} . Sin((ntheta)/( 2) ))/( sin((theta)/(2)) )`

B

`(cos (n+1) theta)/( sin ((theta)/( 2)) )`

C

`( cos ( ((n-1) theta)/(2) ) sin ( ( n theta)/( 2) ) )/( sin"" ( theta)/( 2) )`

D

`(sin ( (n theta)/( 2) ).cos{ (n+1) theta})/( sin ((theta)/( 2) ) )`

Text Solution

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The correct Answer is:
A
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