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If `(tan(alpha + beta - gamma))/(tan(alpha - beta + gamma)) = (tan gamma)/(tan beta), (beta ne gamma)`, then `sin 2alpha + sin 2beta + sin 2gamma=`

A

0

B

1

C

2

D

`1//2`

Text Solution

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The correct Answer is:
A
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AAKASH SERIES-COMPOUND ANGLES-LECTURE SHEET (EXERCISE - I)
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