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If alpha+beta+gamma =2pi, then...

If `alpha+beta+gamma =2pi`, then

A

`"tan"(alpha)/(2)+"tan"(beta)/(2)+"tan"(gamma)/(2)="tan"(alpha)/(2)"tan"(beta)/(2)"tan"(gamma")/(2)`

B

`"tan"(alpha)/(2)"tan"(beta)/(2)+"tan"(beta)/(2)"tan"(gamma)/(2)+"tan"(gamma)/(2)"tan"(alpha)/(2)=1`

C

`"tan"(alpha)/(2)+"tan"(beta)/(2)+"tan"(gamma)/(2)=-"tan"(alpha)/(2)"tan"(beta)/(2)"tan"(gamma)/(2)`

D

`sum tan((alpha)/(2))tan((beta)/(2))=-1`

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The correct Answer is:
A
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AAKASH SERIES-COMPOUND ANGLES-LECTURE SHEET (EXERCISE - I)
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