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Given , cos2^(m)thetacos2^(m+1)theta.......

Given , `cos2^(m)thetacos2^(m+1)theta......cos2^ntheta=(sin2^(n+1)theta)/(2^(n-m+1)sin2^(m) theta) ` where `2^mtheta ne kpi,n,m,k in l` solve the following
`cos2^(3)""(pi)/10cos2^(4)""(pi)/10cos2^(5)""(pi)/10.....cos2^(10)""(pi)/10` is equal to

A

`1/128`

B

`1/256`

C

`1/(512) sin ""(pi)/10`

D

`(sqrt(5)-1)/512 sin"" (3pi)/10`

Text Solution

Verified by Experts

The correct Answer is:
B
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