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If tanalpha = p/q where alpha = 2beta, ...

If `tanalpha = p/q ` where `alpha = 2beta, alpha` being an acute angle then `1/(2)[p"cosec"2beta sec2beta]` is equal to

A

`sqrt(p^2+q^2)`

B

`sqrt(p^2-q^2)`

C

`sqrt(2p^2+q^2)`

D

`2sqrt(p^2+q^2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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