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If cos alpha+ cos beta= a, sin alpha+ si...

If `cos alpha+ cos beta= a, sin alpha+ sin beta= b and alpha- beta= 2 theta`. Then `(cos 3 theta)/(cos theta)=`

A

`a^2+b^2-2`

B

`a^2+b^2-3`

C

`3-a^2-b^2`

D

`(a^2+b^2)//4`

Text Solution

Verified by Experts

The correct Answer is:
B
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