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{:("Column-I", "Column-II"), ("A) "x in[...

`{:("Column-I", "Column-II"), ("A) "x in[pi, 2pi] rArr abs(tan^(-1)(tanx))" can be", "p) "abs(x-2pi)), ("B) "x in [pi, 2pi] rArr abs(cot^(-1)(cotx))" can be", "q) "abs(x-pi)), ("C) "x in [-pi, pi]rArr abs(sin^(-1)(sinx)), "r) "abs(x)), ("D) "x in [-pi, pi] rArr abs(cos^(-1)(cosx)), "s) "abs(x+pi)):}`

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The correct Answer is:
A-pq;B-q;C-qr;D-pr
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