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tan((pi)/4+1/2"cos"^(-1)a/b)+tan((pi)/4-...

`tan((pi)/4+1/2"cos"^(-1)a/b)+tan((pi)/4-1/2"cos"^(-1)a/b)=`

A

b/a

B

a/b

C

2a/b

D

ab/a

Text Solution

Verified by Experts

The correct Answer is:
D
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