Match from List-I to List-II {:("List-...

Match from List-I to List-II
`{:("List-I","List-II"),("(Function)","(Domain)"),(I.sechx,(a)R-[-1,1]),(II.coth^(-1)x,(b)R-{0}),(III.cosh^(-1)x,(c )R),(IV.cothx,(d)[1,oo)),(,(e )[2,oo)):}`

A

c, a, b, d

B

a, c, b, d

C

a, c, d, b

D

c, a, d, b

Text Solution

Verified by Experts

The correct Answer is:

D

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AAKASH SERIES-HYPERBOLIC FUNCTIONS -PRACTICE SHEET EXERCISE-II (STRAIGHT OBJECTIVE TYPE QUESTIONS)

The domain of cos h^(-1) (2x) is
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cos h^(-1) (2) =
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tan h^(-1) ((1)/(2)) + cot h^(-1) (2) =
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tan h^(-1) ((1)/(3))
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If x=tanh^(-1)(y), then log(e )((1+y)/(1-y))=
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If cos h^(-1) (k) = log(e) (3 + 2 sqrt(2)) then k =
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"cosec h"^(-1) ((1)/(5)) =
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e^(sin h^(-1) (cot theta))
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tan h^(-1) ((1)/(2)) =
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If |x| lt 1, then (1)/(2) log((1+x)/(1-x))=
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sec h^(-1) ((1)/(sqrt(2))) =
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If log(sqrt(5)+2)=sinh^(-1)(k) then k =
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e^(log(e)(cos h^(-1)2)) =
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sec h^(-1) ((1)/(3)) =
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sin h^(-1) ((x)/(sqrt(1 - x^(2)))) =
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sec h^(-1) ((2)/(3)) = log(e) (((k + 1) + sqrt(k^(2) + 1))/(k)) then k...
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sec h^(-1) (sin theta) =
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Match from List-I to List-II {:("List-I","List-II"),("(Function)","(...
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