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A tower stands at the center of a circul...

A tower stands at the center of a circular park. A and B are two points on the boundary of the park such that AB(=a) subtends an angle of `60^(@)` at the foot of the tower, and the angle of elevation of the top of the tower from A or B is `30^(@)`. The height of the tower is

A

`(2a)/(sqrt(3))`

B

`2asqrt(3)`

C

`(a)/(sqrt(3))`

D

`asqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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AAKASH SERIES-HEIGHTS AND DISTANCES-LECTURE SHEET Exercise-I (Straight Objective Type Questions)
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