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A tower substends angles alpha,2alpha,3a...

A tower substends angles `alpha,2alpha,3alpha` at A,B,C all lying on horizontal line through the foot of the tower the `AB/BC`=

A

`(Sin3alpha)/(Sin2alpha)`

B

`1+2Cos2alpha`

C

`2+2Cos2alpha`

D

`(Sin2alpha)/(Sinalpha)`

Text Solution

Verified by Experts

The correct Answer is:
B
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