Home
Class 11
MATHS
A chimney leans towards north. At equal ...

A chimney leans towards north. At equal distance due north and south of it in a horizontal plalne, The elevation of the tops are `alpha and beta` respecctively. The inclination of the top of the chimney to the vertical is

A

`Tan^(-1)[(sin(alpha-beta))/(sinalphasinbeta)]`

B

`Tan^(-1)[(2sin(alpha-beta))/(sinalphasinbeta)]`

C

`Tan^(-1)[(sin(alpha-beta))/(2sinalphasinbeta)]`

D

`Tan^(-1)[(sin(alpha-beta))/(2cosalphacosbeta)]`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • HEIGHTS AND DISTANCES

    AAKASH SERIES|Exercise PRACTICE SHEET Exercise-I (Level-I) (Straight Objective Type Questions)|39 Videos
  • FUNCTIONS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|50 Videos
  • HYPERBOLIC FUNCTIONS

    AAKASH SERIES|Exercise PRACTICE SHEET EXERCISE-II (STRAIGHT OBJECTIVE TYPE QUESTIONS)|18 Videos

Similar Questions

Explore conceptually related problems

The elevation of a tower due north of a station A is alpha and at another station B due west of it is beta. If AB=a, the height of the tower is

The elevation of a tower due north of a station A is alpha and at another station B due west of it is beta . If AB =a, the height of the tower is

A tower leans towards west making an angle alpha with the vertical. The angular elevation of B, the top most point of the tower is beta as observed from a point C due east of A at distance d from A. If the angular elevation of B from a point due east of C a distance 2d from C is gamma , " then " 2tan alpha can be written as

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth's magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null-point (i.e., 14 cm) from the centre of the magnet ? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth's magnetic field.)

Two towers A and B, each of height 20m are situated a distance 200m apart. A body thrown horizontally from the top of the tower A with a velocity 20 ms^(-1) towards the tower B hits the ground at point P and another body thrown horizontally from the top of tower B with a velocity 30ms^(-1) towards the tower A hits the ground at point Q. if a car starting from rest from P reaches Q in 10 seconds, then the acceleration of the car is (acceleration due to gravity =10 ms^(-2) )

A long straight horizontal cable carries a current of 2.5 A in the direction 10^(@) south of west to 10^(@) north of east. The magnetic meridian of the place happens to be 10^(@) west of the geographic meridian. The earth's magnetic field at the location is 0.33 G, and the angle of dip is zero. Locate the line of neutral points (ignore the thickness of the cable) ? (At neutral points, magnetic field due to a current-carrying cable is equal and opposite to the horizontal component of earth's magnetic field?.

The angle of elevation of the top of the top of a vertical tower from a point A, due east of it is 45^(@) . The angle of elevation of the top of the same tower from a point B, due south of A is 30^(@) . If the distance between A and B is 54sqrt2m , then the height of the tower (in meters), is