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The elevation of a tower due north of a ...

The elevation of a tower due north of a station A is `alpha` and at another station B due west of it is `beta`. If AB =a, the height of the tower is

A

`(a)/(sqrt(sin^(2)alpha+sin^(2)beta))`

B

`(a)/(sqrt(cos^(2)alpha+cos^(2)beta))`

C

`(a)/(sqrt(tan^(2)alpha+tan^(2)beta))`

D

`(a)/(sqrt(cot^(2)alpha+cot^(2)beta))`

Text Solution

Verified by Experts

The correct Answer is:
D
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