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f(x+1)=f(x) + f(1) , f(x), g(x) : N to N...

`f(x+1)=f(x) + f(1) , f(x), g(x) : N to N`
`g(x)` = any arbitrary function and `fog(x)` is one-one

A

If fog is one-one, then g is one-one

B

If f is onto, then `f(n)=n AA n in N`

C

f is one-one

D

If g is onto, then fog is one-one

Text Solution

Verified by Experts

The correct Answer is:
D
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JEE MAINS PREVIOUS YEAR-JEE MAIN 2021-SECTION-A
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