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A curve y=ax^2+bx+c passing through the ...

A curve `y=ax^2+bx+c` passing through the point `(1,2)` has slope of tangent at orign equal to 1 , then ordered triplet `(a,b,c)` may be

A

`a=1/2, b=1/2, c=1`

B

a = 1, b = 0, c= 1

C

a = 1, b = 1, c = 0

D

a = -1, b = 1, c = 1

Text Solution

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The correct Answer is:
C
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