Home
Class 12
MATHS
The common chord of the circles x^(2)+y^...

The common chord of the circles `x^(2)+y^(2)-4x-4y=0 and 2x^(2)+2y^(2)=322` subtends at the origin an angle equal to

A

`(pi)/(3)`

B

`(pi)/(4)`

C

`(pi)/(6)`

D

`(pi)/(2)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2016

    WB JEE PREVIOUS YEAR PAPER|Exercise MULTIPLE CHOICE QUESTIONS|75 Videos

  • QUESTION PAPER 2018

    WB JEE PREVIOUS YEAR PAPER|Exercise MULTIPLE CHOICE QUESTIONS|75 Videos

Similar Questions

Explore conceptually related problems

The common chord of the circles x^(2)+y^(2)-4x-4y=0and2x^(2)+2y^(2)=32 subtends at the origin an angle equal to

The common chord of x^2+y^2-4x-4y=0 and x^2+y^2=16 subtends at the origin an angle equal to

Find the equation of the common chord of the two circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 and show that this chord is perpendicular to the line joining the two centres.

Find the equation of the common chord of the two circles x^(2)+y^(2)-4x - 10y - 7 = 0 and 2x^(2) + 2y^(2) - 5x + 3y + 2 = 0 . Show that this chord is perpendicular to the line joining the centres of the two circles.

Find the equation to the circle described on the common chord of the given circles x^(2) + y^(2) - 4x - 5 = 0 and x^(2) + y^(2) + 8x + 7 = 0 as diameter.

Find the equation to the circle described on the common chord of the circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 as diameter.

The length of the common chord of the two circles x^2+y^2-4y=0 and x^2+y^2-8x-4y+11=0 is

Find the equation to the common chord of the two circles x^(2) + y^(2) - 4x + 6y - 36 = 0 and x^(2) + y^(2) - 5x + 8y - 43 = 0 .

The length of the common chord of the parabolas y^(2)=x and x^(2)=y is

The common chord of the circle x^2+y^2+6x+8y-7=0 and a circle passing through the origin and touching the line y=x always passes through the point. (a) (-1/2,1/2) (b) (1, 1) (c) (1/2,1/2) (d) none of these

WB JEE PREVIOUS YEAR PAPER-QUESTION PAPER 2017-Multiple Choice Questions
  1. The point P (3, 6) is first reflected on the line y = x and then the i...

    Text Solution

    |

  2. Let d(1) and d(2) be the lengths of the perpendiculars drawn from any ...

    Text Solution

    |

  3. The common chord of the circles x^(2)+y^(2)-4x-4y=0 and 2x^(2)+2y^(2)=...

    Text Solution

    |

  4. The locus of the mid-points of the chords of the circle x^(2)+y^(2)+2x...

    Text Solution

    |

  5. Let P be the foot of the perpendicular from focus S of hyperbola (x^(2...

    Text Solution

    |

  6. B is an extremity of the minor axis of an ellipse whose foci are S and...

    Text Solution

    |

  7. The axis of the parabola x^(2)+2xy+y^(2)-5x+5y-5=0 is

    Text Solution

    |

  8. The line segment joining the foci of the hyperbola x^(2)-y^(2)+1=0 is ...

    Text Solution

    |

  9. The equation of the plane through (1,2,-3) and (2,-2,1) and parallel t...

    Text Solution

    |

  10. Three lines are drawn from the origin O with direction cosines proport...

    Text Solution

    |

  11. Consider the non-constant differentiable function f of the one variabl...

    Text Solution

    |

  12. If f(x)=log(5)log(3)x, then f'(e ) is equal to

    Text Solution

    |

  13. Let F(x)=e^(x),G(x)=e^(-x) and H(x)=G(F(x)), where x is a real variabl...

    Text Solution

    |

  14. If f''(0)=k,kne0 then the value of lim(xrarr0)(2f(x)-3f(2x)+f(4x))/(x^...

    Text Solution

    |

  15. If y=e^(msin^(-1)x), then (1-x^(2))(d^(2)y)/(dx^(2))-x(dy)/(dx)-ky=0. ...

    Text Solution

    |

  16. The chord of the curve y=x^(2)+2ax+b. Joining the points where x=alpha...

    Text Solution

    |

  17. Let f(x)=x^(13)+x^(11)+x^(9)+x^(7)+x^(5)+x^(3)+x+19. Then f(x)=0 has

    Text Solution

    |

  18. Let f(x)={{:(x^(p)/((sinx)^(q))" , if "0ltxle(x)/(2)),(" 0 ,...

    Text Solution

    |

  19. lim(xrarr0)(sinx)^(2tanx)

    Text Solution

    |

  20. intcos(logx)dx=F(x)+c, where c is an arbitrary constant. Here F(x) =

    Text Solution

    |