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intcos(logx)dx=F(x)+c, where c is an arb...

`intcos(logx)dx=F(x)+c`, where c is an arbitrary constant. Here F(x) =

A

`x[cos(logx)+sin(logx)]`

B

`x[cos(log(x)-sin(logx)]`

C

`(x)/(2)[cos(logx)+sin(logx)]`

D

`(x)/(2)[cos(logx)-sin(logx)]`

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WB JEE PREVIOUS YEAR PAPER-QUESTION PAPER 2017-Multiple Choice Questions
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