Home
Class 12
PHYSICS
A photon of wavelength 300 nm interacts ...

A photon of wavelength 300 nm interacts with a stationary hydrogen atom in ground state. During the interaction, whole energy of the photon is transferred to the electron of the atom. State which possibility is correct. Consider, Plank constant `=4x10 ""^(15)evs`, velocity of light `=3 xx 10^(8) m//s` ionization energy of hydrogen=13.6eV)

A

Electron will be knocked out of the atom

B

Electron will go to any excited state of the atom

C

Electron will go only to first excited state of the atom

D

Electron will keep orbiting in the ground state of atom

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2015

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY II)|4 Videos

  • QUESTION PAPER 2015

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|5 Videos

  • QUESTION PAPER 2014

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|3 Videos

  • QUESTION PAPER 2016

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS|40 Videos

Similar Questions

Explore conceptually related problems

A photon of wavelength 300 nm interracts with a stationary hydrogen atom in ground state. During the interaction, whole energy of the photon I transferred to the electron os the atom. State which possibility is correct. (Consider,Planck's constant =4xx10^(-15)eV *s , velocity of light =3xx10^(8)m//s , ionisation energy of hydrogen =13.6 eV.

The work function of metals is in the range of 2 eV to 5 eV. Find which of the following wavelength of light cannot be used for photoelectric effect. (Consider, Planck's constant = 4 xx 10^(-15) eV.s , velocity of light = 3 xx 10^(8) m//s )

The total energy of an electron in the first excited state of hydrogen atom is -3.4 eV . What is the potential energy of the electron in this state ?

The ground state energy of hydrogen atom is -13.6 eV. what are the kinetic and potential energies of the electron in this state ?

An electron in a hydrogen -like atom is in an excited state. It has a total energy of -3.4 eV. Calculate the kinetic energy of the electron.

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV . In this state (b) what is the potential energy of the electron ?

A photon of wavelength 4x10^-7 m strikes a metal surface work function of the metal is 2.13eV calculate the kinetic energy of the emitted photoelectrons in eV

The ionization energy of the hydrogen atom is 13.6eV. The potential energy of the electron in n=2 state of hydrogen atom is

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV . In this state (a) what is the kinetic energy of the electron ?