Home
Class 12
PHYSICS
In the circuit shown below, the switch i...

In the circuit shown below, the switch is kept in position 'a' for a long time and is then thrown to position 'b'. The amplitude of the resulting oscillating current is given by

A

`Esqrt(L//C)`

B

E/R

C

infinity

D

`Esqrt(C//L)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2015

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|5 Videos

  • QUESTION PAPER 2015

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|5 Videos

  • QUESTION PAPER 2014

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|3 Videos

  • QUESTION PAPER 2016

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS|40 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown in figure switch s is closed at time t = 0. Find the current through different wires and charge stored on the capacitor at any time t.

What is the current I shown in the given circuit ?

In a plane electromagnetic wave, the electric field (E) having amplitude of 48 . V m^(-1) oscillates at a frequency of 2.0 xx 10^10 Hz. The amplitude of the oscillating magnetic field (B) is

A moving particle has an acceleration a = -bx, where b is a positive constant and x is the distance of the particle from the equilibrium position. What is the time period of oscillation of the particle?

A capacitor of 2muF is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is :