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An electron of mass 'm' is accelerated b...

An electron of mass 'm' is accelerated by a potential difference V and the corresponding de-Broglie wavelength is `lamda` The de Broglie wavelength of a proton of mass M if it is accelerated by the same potential difference is.

A

`lamda(m/M)`

B

`lamda(M/m)`

C

`lamdasqrt(m/M)`

D

`lamdasqrt(M/m)`

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