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A photon of energy 8eV is incident on a...

A photon of energy `8eV` is incident on a metal plate with threshold frequency `1.6 xx 10^(15)` Hz. The maximum kinetic energy of the emitted photo electrons is (given h= `6 xx 10^(-34) Js`)

A

6 eV

B

1.6 eV

C

1.2 eV

D

2 eV

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For any metal the photoelectric threshold wavelength is 3800overset@A . An ultraviolet wave of wavelength 2000overset@A is incident on the metal then what will be- the maxinum kinetic energy of the photoelectrons. [given— h = 6.62 xx 10^(-34)J.S]

For photoelectric emission, threshold wavelength of a metal is 2460 Å . If ultraviolet light of wavelength 1810 Å be incident on the metal, what will be the maximum kinetic energy of the emitted electrons? [Planck's constant = 6.62xx10^(-34) J.s , velocity of light in veccuum = 3xx10^(8) m.s^(-1) ]

Einstein's equation for photoelectric effect is E_("max") = hf - W_(0) , where h = Planck's constant = 6.625 xx 10^(-34) J.s, f = frequency of light incident on metal surface, W_(0) = work function of metal and E_("max") = maximum kinetic energy of the emitted photoelectrons. It is evident that if the frequency f is less than a minimum value f_(0) or if the wavelength lamda is greater than a maximum value lamda_(0) , the value of E_("max") would be negative, which is impossible. Thus for a particular metal surface f_(0) is the threshold frequency and lamda_(0) is the threshold wavelength for photoelectric emssion to take place. Again if the collector plate is ketp at a negative potential with respect to the emitter plate, the velocity of the photoelectrons would decrease. The minimum potential for which the velocity of the speediest electron becoes zero, is known as the stopping potential, the photoelectric effect stops for a potential lower than this. [velocity of light = 3xx 10^(8) m.s^(-1) , mass of an electron m = 9.1 xx 10^(-31) kg , charge of an electron, e = 1.6 xx 10^(-19)C The threshold wavelength of photoelectric effect for a metal surface is 4600 Å . Work function of the metal (in eV) is

Threshold frequency of a metal is 5xx10^(13)s^(-1) upon which 1xx10^(14)s^(-1) frequency light is focused. Then the maximum kinetic energy of emitted electron is-

A stream of photons of energy 10.6 eV and intensity 2.0 W m^(-2) is incident on a platinum surface. Area of the surface is 1.0 xx 10^(-4) m^(2) and its work function is 5.6 eV. 0.53 % of incident photons emit photoelectrons. Find the number of photoelectrons emitted per second and maximum and minimum energies of the emitted photoelectrons in eV. (1eV = 1.6 xx 10^(-19)J)

Frequency of a photon is 1.2xx10^(15)Hz . Calculate its energy in J.

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. maximum kinetic energy of emitted photoelectron. (h = 6.63 xx 10^(-27) " erg.s")

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