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The emf of a Daniel cell at 298 K is E1 ...

The emf of a Daniel cell at 298 K is `E_1` The cell is
`Zn|ZnSO_(4)(0.01M)||CuSO_(4)(1M)|Cu`
When the concentration of `ZnSO_4` is changed to 1M and that of `CuSO_4` , to 0.01 M, the emf changes to `E_2` The relationship between `E_1 and E_2` will be

A

`E_1 - E_(2)=0`

B

`E_1 lt E_2`

C

`E_1 gt E_2`

D

`E_1 = 10^2 E_2`

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