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CH(3)-C-=C MgBr can be prepared by the r...

`CH_(3)-C-=C MgBr` can be prepared by the reaction of

A

`CH_(3)-C-=C` Br with `MgBr_(2)`

B

`CH_(3)-C-=CH` with `MgBr_(2)`

C

`CH_(3)-C-=CH` with KBr and Mg metal

D

`CH_(3)-C-=CH` with `CH_(3)MgBr`

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