`0.05 M Ba(OH)_(2)` विलयन का pH है -

Options

A. 12
B. 13
C. 1
D. `10`

Answer

B

Explanation

`underset(0.05M)(Ba(OH)_(2)) rarr Ba^(2+) + underset(2 xx 0.05 M = 0.1 M)(2OH^(-))`
`pOH = -log[OH^(-)] = -log 0.1 = 1`
`pH = 14-1 = 13`