Home
Class 12
CHEMISTRY
A conductivity cell has been calibrated ...

A conductivity cell has been calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance, `k=1.25xx10^(-3)5cm^(-2)`) in the cell and the measured resistance was 800 ohms at `25^(@)C`. The cell constant will be

A

`1.02cm^(-1)`

B

`0.102cm^(1)`

C

`1.00cm^(-1)`

D

`0.5cm^(-1)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2013

    WB JEE PREVIOUS YEAR PAPER|Exercise CATEGORY-II|10 Videos
  • QUESTION PAPER 2013

    WB JEE PREVIOUS YEAR PAPER|Exercise CATEGORY-III|5 Videos
  • QUESTION PAPER 2012

    WB JEE PREVIOUS YEAR PAPER|Exercise Subject: Chemistry|41 Videos
  • QUESTION PAPER 2015

    WB JEE PREVIOUS YEAR PAPER|Exercise CHEMISTRY (CATEGORY III)|5 Videos

Similar Questions

Explore conceptually related problems

A conductivity cell has beeen calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance, kappa =1.25xx10^(-3)"S.cm"^(-1) ) in the cell and the measured resistance was 800 ohm at 25^(@)C . The cell constant will be -

At a definite temperature, a conductivity cell is filled with 0.02 (N) KCl solution, the resistance is 380 ohm. If the specific conductance of 0.02(N) KCl solution at the same temperature be "0.002758 ohm.cm"^(-1) . Find the cell constant. If the distance between the electrodes is 0.80 cm, what is the average area of the electrodes?

0.0024 (M) Acetic acid solution has specific conductance 7.896xx10^-5 S cm^-1 . What is the molar conductance of ACOH and also find degree of dissociation of it?

A conductivity cell has a cell constant of "0.5 cm"^(-1) . This cell when filled with 0.01 M NaCl solution has a resistance of "384 ohm at "25^(@)C . Calculate the equivalent conductance of the given solution.

Area of each electrode of a conductivity cell is "1.25 cm"^(2) . The cell is filled with a solution of resistance of 160 ohm. If specific conductance of the solution is "0.016 ohm"^(-1)."cm"^(-1) , calculates the distance between the electrodes, and the cell constant.

Calculate the molar conductance of 0.01 (M) KCI solution. Sp. conductance of KCI is 0.07 cm^(-1) ohm^(-1) . Define molar conductance?

A conductance cell has platinum electrodes, each with 5 cm^(2) area and separated by 0.5 cm distance. What is the cell constant?

Resistance is 82.3 ohm, when a conductivity cell is filled with 0.02 (N) KCl solution at a definite temperature. At the same temperature, the specific conductance of 0.02 (N) KCl solution is "0.002758 ohm.cm"^(-1) . The resistance is 324 ohm when the cell is filled with :0.05 (N)K_(2)SO_(4) solution. Calculated the equivalent and molar conductivity of K_(2)SO_(4) solution.

In a conductivity cell, the distance between the two Pt electrodes is 2.0 cm and each electrode has cross - sectional area of 4.0cm^(2) . When the cell is filled with a 0.4 molar solution of an electrolyte, the reistance of the cell 25Omega . Calculate the molar conductivity of the solution.