300 grams of water at 80^(@)C are poured...

300 grams of water at `80^(@)C` are poured on a large block of ice at `0^(@)C`. The mass of ice that melts is

80 gm

30 gm

800 gm

300 gm

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10g of water at 30^(@)C and 5g of ice at -20^(@) C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice= 0.5 cal g^(-1) (""^(0)C)^(-1) and latent heat of fusion of ice =80 cal g^(-1)

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When 30 g water at 50^(@)C is poured into a calorimeter at a temperature 15^(@)C , the final temperature attained is 20^(@)C . What is the water equivalent of the calorimeter?

Calculate (1) the enthalpy change in the fusion of 100 g ice at 0^(@)C temperature and 1 atm pressure pressure (2) the enthalpy change in the vaporisation of 10g water at 100^(@)C temperature and 1 atm pressure. Givenn : Latent heat of ice at 0^(@)C temperature and 1 atm pressure =6.02kJ*mol^(-1) and latent heat of vaporisation of water at 100^(@)C temperature= 40.4kJ*mol^(-1) .

The water equivalent of a calorimeter is 10g and it contains 50 g of water at 15^(@)C . Some amount of ice, initially at -10^(@)C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice =0.5"cal"gm^(-1)""^(@)C^(-1) specific heat of water =1.0"cal"gm^(-1)""^(@)C^(-1) and laten heat of melting of ice =80"cal"gm^(-1) )?

540 gm of ice at 0^@ is mixed with 540 gm of water at 80^@C . The final temperature of the mixture is

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