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A capacitor of capacitance C(0) is charg...

A capacitor of capacitance `C_(0)` is charged to a potential `V_(0)` and is connected with another capacitor of capacitance C as shown. After closing the switch S, the common potential across the two capacitors becomes V, The capacitance C is given by

A

`(c_(0)(V_(0)-V))/(V_(0))`

B

`(c_(0)(V-V_(0)))/(V_(0))`

C

`(c_(0)(V+ V_(0)))/(V)`

D

`(c_(0)(V_(0)-V))/(V)`

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