Home
Class 12
PHYSICS
A particle is moving with a uniform spee...

A particle is moving with a uniform speed v in a circular path of radius r with the centre at O. When the particle moves from a point P to Q on the circle such that `anglePOQ= theta`, then the magnitude of the change in velocity is

A

`2v sin (2 theta)`

B

zero

C

`2v sin ((theta)/(2))`

D

`2 v cos ((theta)/(2))`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2013

    WB JEE PREVIOUS YEAR PAPER|Exercise Category-II|10 Videos

  • QUESTION PAPER 2013

    WB JEE PREVIOUS YEAR PAPER|Exercise Category-III|5 Videos

  • QUESTION PAPER 2012

    WB JEE PREVIOUS YEAR PAPER|Exercise Subject: Physics|38 Videos

  • QUESTION PAPER 2014

    WB JEE PREVIOUS YEAR PAPER|Exercise PHYSICS (CATEGORY III)|3 Videos

Similar Questions

Explore conceptually related problems

A body revolving with uniform speed v in a circular path of radius r. The tangential acceleration is

A particle is moving with a uniform speed in a circular orbit of radius R in a central force inversely proportional to the n th power of R. If the period of rotation of the particle is T, then

A particle is moving with a constant speed v in a circle. What is the magnitude of average velocity after half rotation?

A charge q is revolving along a circular path of radius r with velocity v . Determine its magnetic moment .