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Find the equation of the pair of lines t...

Find the equation of the pair of lines throughh the origin and forming an equilateral triangle with the line `x-2y-1=0`. Find also the area of triangle.

Text Solution

Verified by Experts

The correct Answer is:
`(1)/(5sqrt(3))` sq. units
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Knowledge Check

  • The equation to the pair of lines through the origin and forming an equilateral triangle with the line 4x – 3y + 1 = 0 is

    A
    `11x^(2)+96xy+39y^(2)=0`
    B
    `11x^(2)+96xy-39y^(2)=0`
    C
    `11x^(2)+96xy+39y^(2)=0`
    D
    `11x^(2)-96xy-39y^(2)=0`
  • The equation of pair of lines passing through origin and forming an equlateral triangle with the line 3x + 4y -5 = 0 is

    A
    `39x^(2) +11y^(2) - 96xy =0`
    B
    `x^(2) + y^(2) -4xy = 0`
    C
    `x^(2) -7xy + 12y^(2)=0`
    D
    `2x^(2) + 6xy + y^(2) = 0`
  • Equation of pair of lines through (0,0) and forming an equilateral triangle with the line x-3y+4=0 is

    A
    `23x^(2)+3y^(2)-8xy=0`
    B
    `13x^(2)-3y^(2)+12xy=0`
    C
    `23x^(2)+3y^(2)-16xy=0`
    D
    `23x^(2)+3y^(2)++48xy=0`
  • Similar Questions

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    Show that the lines x^(2)+16xy-11y^(2)=0 form an equilateral triangle with the line 2x+y+1=0 and find its area.

    The equation of the pair of perpendicular lines passing through origin and forming an isosceles triangle with the line 2x+3y=6 is

    The equation of the pair of perpendicular lines passing through origin and forming an isosceles triangle with the line 2x+3y=6 , is

    The area of the equilateral triangle formed by the pair of lines passing through the origin with the line x-y+1=0 is