If one jine of the pair of lines `ax^2+2hxy+by^2=0` bisects the angle between the coordinate axes, then prove that `(a+b)^2=4h^2`.

If one of lines in ax^(2)+2hxy+by^(2)=0 bisects the angle between the coordinates axes then (a+b)^(2)=

Statement 1: If -2h =a+b , then one line of the pair of lines ax^(2)+2hxy+by^(2)=0 bisects the angle between coordinate axes in positive quadrant. Statement 2: If ax + y (2h + a) = 0 is a factor of ax^(2)+2hxy+by^(2)=0 , then b + 2h +a=0

If one the lines in the pair of stright lines given by 4x^2+6xy+ky^2=0 bisects the angle between the coordinate axes, then k in

If one of the lines in the pair of straight lines given by 4x^(2)+6xy+ky^(2)=0 bisects the angle between the coordinate axes, then k in

If the lines ax^(2) + 2hxy + by^(2)= 0 are equally inclined with the coordinate axes then

If one of the lines of the pair ax^(2)+2hxy+by^(2)=0 bisects the angle between positive direction of the axes then a, b, h satisfy the relation