Home
Class 11
MATHS
Number of solution of 2^(|sinx|)=|cosx|x...

Number of solution of `2^(|sinx|)=|cosx|x in [0,2pi]` is ________

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • TRIGNOMETRIC EQUATIONS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III (MORE THAN ONE CORRECT ANSWER Type Questions)|2 Videos
  • TRIGNOMETRIC EQUATIONS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III (INTEGER TYPE QUESTIONS )|1 Videos
  • TRIGNOMETRIC EQUATIONS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-II (Integer Type Questions)|5 Videos
  • TRANSFORMATIONS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I LEVEL-I Straight Objective Type Questions)|41 Videos
  • TRIGONOMERTIC RATIOS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|77 Videos

Similar Questions

Explore conceptually related problems

The total number of solutions of log_(e)|sinx|=-x^(2)+2x in [-pi/2,pi/2] is equal to

The total number of solutions of cos x=sqrt(1-sin2x) in [0,2pi] is equal to

The number of stationary points of f(x) = cosx in [0,2pi] are

The number of solutions of cosx=|1+sinx|,0lexle3pi is

No. of solutions of |cosx|=sinx,0lexle4pi , is

Number of solutions of |cosx|=2[x] is (Where [x] is integral part of x)

The number of solutions of sin^(4)x-cos^(2)xsinx+2sin^(2)x+sinx=0 in 0lexle 3pi is

The number of solutions of the equation 2x=3pi(1-cosx) is

The number of solutions of the equation x^(3)+2x^(2)+5x+2cosx=0 in [0,2pi] is