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tan|x|=|tanx| if x in (k in Z)...

`tan|x|=|tanx|` if `x in (k in Z)`

A

`(-((2k+1)pi)/2,-pik],kge0`

B

`[pik,(2k+1)(pi)/2),kge0`

C

`(-pik, (pi(2k+1))/2), kge0`

D

`(pik, (-pi(2k-1))/2), kle0`

Text Solution

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The correct Answer is:
A, B, D
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AAKASH SERIES-TRIGNOMETRIC EQUATIONS-LECTURE SHEET (EXERCISE-III (MORE THAN ONE CORRECT ANSWER Type Questions)
  1. Let x,y,z be elements from interval [0,2pi] satisfying the inequality ...

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  2. tan|x|=|tanx| if x in (k in Z)

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