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If sin^(2)x-asinx+b=0 has only one solut...

If `sin^(2)x-asinx+b=0` has only one solution in `(0,pi)` then which of the following statemnets are correct?

A

`a in (-oo, 1]uu[2,oo)`

B

`b in (-oo, 0]uu[1,oo)`

C

`a=1+b`

D

`ain (-oo,0)uu(0,oo)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
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