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If sin^(3) theta cos theta - cos ^(3) th...

If `sin^(3) theta cos theta - cos ^(3) theta sin theta = 1 //4 " then " theta` =

A

`theta=(n pi)/2+(pi)/8n in Z`

B

`theta=(npi)/2-(pi)/8 n in Z`

C

`theta=(n pi)/2+(pi)/4 n in Z`

D

`theta=(n pi)/2-(pi)/4n in Z`

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The correct Answer is:
B
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