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e^(|sin x|)+ e^(-|sin x|) + 4 a = 0 wil...

`e^(|sin x|)+ e^(-|sin x|) + 4 a = 0 ` will have exactly four different solutions in `[0, 2 pi]` is

A

`a in R`

B

`a in [-e/4-1/4]`

C

`a in [-(1-e^(2))/(4e)-oo]`

D

`a in [1/4, e/4]`

Text Solution

Verified by Experts

The correct Answer is:
D
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