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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where `AB = a.` The boy at B starts runing in a direction pependicular to AB with velocity `v_(1)`. The boy at A starts runing simultaneously with velocity is v and catches the other boy is time t, where t is

A

`a// sqrt(v^(2)+v_(1)^(2))`

B

`(a)/(sqrt(v^(2)-v_(1)^(2)))`

C

`a//(v-v_(1))`

D

`a(v+v_(1))`

Text Solution

Verified by Experts

The correct Answer is:
B
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