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A particle is projected from the ground ...

A particle is projected from the ground with velocity u making an angle `theta` with the horizontal. At half of its maximum heights.

A

its horizontal velocity is a cos `theta`

B

its vertical is `( u sin theta)/(sqrt(2))`

C

its velocity is `u ((1+Cos^(2)theta)/(2))^(1/2)`

D

all the above are true

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The correct Answer is:
D
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