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The horizontal distance x and the vertic...

The horizontal distance x and the vertical height y of a projectile at time t are given by `x = a t` and `y = bt^(2)+ct` where a, b and c are constants. Then

A

The speed of the projectile 1 second after it is fired is `(a^(2)+b^(2)+c^(2))^(1//2)`

B

The angle with the horizontal at which the projectile is fired is `tan^(-1)(c//a)`

C

The acceleration due to gravity is `-2b`

D

The initial speed of the projectile is `(a^(2)+c^(2))^(1//2)`

Text Solution

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The correct Answer is:
B, C, D
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