A particle starts with initial velocity ...

A particle starts with initial velocity 4m/s and moves such that acceleration is given by `a = sqrt(V)`
It's velocity after a displacement of `(38)/(3)` m is

9 m/s

`6^(2//3) m//s`

3 m/s

6 m/s

Verified by Experts

The correct Answer is:

KINEMATICS
AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I) Horizontal Motion (LEVEL - II) (Matrix Matching Type Questions)|1 Videos
KINEMATICS
AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I) Horizontal Motion (LEVEL - II) (Integer Type Questions)|2 Videos
KINEMATICS
AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I) Horizontal Motion (LEVEL - II) (More than One correct answer Type Questions)|4 Videos
HORIZONTAL CIRCULAR MOTION
AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED) Integer Type Questions)|3 Videos
KINETIC THEORY OF GASES
AAKASH SERIES|Exercise Practice Exercise|15 Videos

Similar Questions