A car accelerates from rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta` and comes to rest. If the total time elapsed is t, then the maximum velocity aequired by the car is

Options

A. `((alpha^(2)+beta^(2))/(alpha beta))t`
B. `((alpha^(2)+beta^(2))/(alpha beta))t`
C. `(alpha beta t)/(alpha + beta)`
D. `((alpha + beta)t)/(alpha beta)`

Answer

C