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A full-wave p-n diode rectifier uses a l...

A full-wave p-n diode rectifier uses a load resistor of `1500Omega`. No filter is used. The forward bias resistance of the diode is `10Omega`. The efficiency of the rectifier is

A

`81.2%`

B

`40.6%`

C

`80.4%`

D

`40.2%`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • A full-wave p-n diode rectifier uses a load resistor of 1500 Omega . No filter is used. The forward bias resistance of the diode is 102. The efficiency of the rectifier is

    A
    `81.2%`
    B
    ` 40.6%`
    C
    `80.4%`
    D
    `40.2% `

  • A full wave p-n junction diode rectifier uses a load resistance of 1300 Omega . The internal resistance of each diode is 9 Omega . Find the efficiency of this full wave rectifier.

    A
    `72% `
    B
    ` 80.64%`
    C
    `75% `
    D
    `79%`

  • In a half wave rectifier, a p-n junction diode with internal resistance 2 Omega is used. If the load resistance of 2 Omega is used in the circuit, then find the efficiency of this half wave rectifier.

    A
    `30.2% `
    B
    `38%`
    C
    `40.2 %`
    D
    `44% `

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    A p-n diode is used in a half wave rectifier with a load resistance of 1000 Omega . If the forward resistance ( r_f ) of diode is 10 Omega , calculate the efficiency of this half wave rectifier.

    A full wave rectifier uses two diodes with a load resistance of 100 Omega . Each diode is having negligible forward resistance. Find the efficiency of this full wave rectifier

    A full wave rectifier uses two diodes with a load resistance of 100Omega . Each diode is having negligible forward resistance. Find the efficiency of this full wave rectifier.

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