`"(i) "sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta`

sin^(4)theta+cos^(4)theta=1-2sin^(2)theta cos^(2)theta

Prove that sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

sin^(4)theta+sin^(2)theta cos^(2)theta=

Prove that (sin^(4)theta-cos^(4)theta)/(sin^(2)theta-cos^(2)theta)=1

If : sin^(4)theta+cos^(4)theta+sin^(2)theta*cos^(2)theta=1-u^(2), "then" : u=

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

Solve cos^(4)theta-sin^(4)theta=cos^2theta

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)