`Sin[pi/3-sin^(-1)(-1/2)]`

Similar Questions

Explore conceptually related problems

Evaluate following 1. sin(cos^(-1) 3//5) 2. cos(tan^(-1)3//4) 3. sin(pi/2-sin^(-1) (-1/2))

sin[(pi)/(2)-sin^(-1)-1/2]

sin(pi/6-sin^(-1)(-1/2))=?

sin[(pi)/(2)-sin^(-1)(-(1)/(2))]

Evaluate the following (i) sin ( pi/2 - sin^(-1) ( (-1)/2)) (ii) sin(pi/2 - sin^(-1)(- sqrt3/2))

sin[sin^(-1) (-(1)/(2))+ (pi)/(3)]=?

The value of sin [ (pi)/(3) - sin^(-1) (- (sqrt(3))/(2))]

Evaluate : sin[pi/2 - sin^(-1) (- sqrt(3)/2)]

Evaluate sin{pi/2-sin^(-1)(-sqrt(3)/2)} .

Find the values of sin{(pi)/(6)-sin^(-1)(-(sqrt(3))/(2))}