`sin^(2)y + cos xy = k`

If a = x cos ^ (2) a + y sin ^ (2) A then (xa) (ya) + (xy) ^ (2) sin ^ (2) A cos ^ (2) A =

If sin ^(2) y+cos (xy)=pi ,then (dy)/(dx) =

If the solution of the differential equation x^2dy + 2xy dx = sin x dx is x^(k)y + cos x = C (where C is an arbitrary constant), then the value of k is equal to

The value of the expression 1- (sin^(2)y)/(1+ cos y) + (1+ cos y)/(sin y) -(sin y)/(1- cos y) is

If sin x + cos y = (1) / (3) and cos x + sin y = (3) / (4) then tan ((xy) / (2)) =

If sin^(2)x+2cos y+xy=0 then (dy)/(dx)=

cos (yz) + cos (zx) + cos (xy) = - (3) / (2) prove that cos x + cos y + cos z = 0 = sin x + sin y + sin

Find quad (dy)/(dx) in the following: sin^(2)y+cos xy=pi

The value of the expression 1- (sin ^ (2) y) / (1 + cos y) + (1 + cos y) / (sin y) - (sin y) / (1-cos y) is equal to

lf_ (cos x + cos y-cos z = 0 = sin x + sin y + sin) then cos ((xy) / (2)) =