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A uniform rod of mass M(1) is hinged at...

A uniform rod of mass `M_(1)` is hinged at its upper end. A particle of mass `M_(2)` moving horizontally strikes the rod at its mid point elastically. If the particle comes to rest after collision, the value of `(M_(1))/(M_(2))` is -

A

`(3)/(4)`

B

`(4)/(3)`

C

`(2)/(3)`

D

`(3)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`L_(H)=M_(2)v (L)/(2)=(M_(1)L^(2))/(3)omega`
`omega=(2M_(2)v)/(2M_(1)L)" "…(1)`
for `e=1, v_(CM)=v -(omegaL)/(2)" "…(2)`
`rArr (2v)/(L)=(3M_(2)v)/(2M_(1)L)`
`rArr (M_(1))/(M_(2))=(3)/(4)`
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