The total speed of a projectile at its greater height is `sqrt(6/7)` of its speed when it is at half of its greatest height. The angle of projection will be :-

The speed of a projectile when it is at its greatest height is sqrt(2//5) times its speed at half the maximum height. The angle of projection is

The velocity of a projectile when it is at the greatest height is (sqrt (2//5)) times its velocity when it is at half of its greatest height. Determine its angle of projection.

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is .

The ratio of the speed of a projectile at the point of projection to the speed at the top of its trajectory is x. The angle of projection with the horizontal is

Choose the correct option (i) The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is 60^(@) . (ii) A missile is fired for maximum range with an initial velocity of 20 m//s , the range of the missile is 40 m . (iii) A ball is projected with a kinetic energy E at an angle of 45^(@) to the horizontal. At the highest point during its flight, its kinetic energy will be E//2 . (iv) An object is projected at an angle of 45^(@) with horizontal. The horizontal range and the maximum height will be in the ratio 4:1

The speed of a projectile at its maximum height is sqrt3//2 times its initial speed. If the range of the projectile is n times the maximum height attained by it, n is equal to :

The horizontal range of a projectile is 4 sqrt(3) times its maximum height. Its angle of projection will be