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7g of MgCO3 after reaction with 14 g sol...

7g of `MgCO_3` after reaction with 14 g solution of `H_2SO_4` left 0.7 g of `MgCO_3` unreacted calculate the percentage strength of `H_2SO_4`.

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The correct Answer is:
`52.5%` (w/w)
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